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PAST QUESTIONS 2003
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Try the questions first, using not more than 15 minutes for each question, and watch the accompanying videos to see how the questions are solved.
Question 1
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If \(A\) and \(B\) are subsets of the universal set, \(ξ\), list the members of \(A\) and \(B\).
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Find the set
\((i)\) \(A \cap B\)
\((ii)\) \(A \cup B\) -
\((i)\) Illustrate \(ξ\), \(A\) and \(B\) on a Venn diagram
\((ii)\) Shade the region for prime factors of 18 on the Venn diagram.
\(ξ\) = {1, 2, 3, 4, ..., 18};
\(A\) = {Prime numbers} and
\(B\) = {Odd numbers greater than 3}
Solution
Question 2
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If \(2n - 5m + 10 = 0\), find
\((i)\) \(m\), when \(n = 2\)
\((ii)\) \(n\), when \(m = 5\)
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Simplify \(\frac{6.4 \times 0.25 \times 16}{0.8 \times 0.5}\) leaving your answer in standard form.
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A number of sweets were shared among 8 children and each child received 30. If 12 children shared the same number of sweets, how many will each receive?
Solution
Solution
Solution
Question 3
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Find
\((i)\) the modal age
\((ii)\) the mean age.
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Draw a bar chart for the distribution.
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What is the probability that a child chosen from the school is 4 years old?
The table shows the distribution of the ages (in years) of children in a nursery school.

Solution
Question 4
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If \(\mathbf{p} = \begin{pmatrix}4 \\ 5 \end{pmatrix}\), \(\mathbf{q} = \begin{pmatrix}0 \\ -2 \end{pmatrix}\) and \(\mathbf{r} = \begin{pmatrix}-3 \\ 7 \end{pmatrix}\),
Find \(\mathbf{p} + 2\mathbf{q} + \mathbf{r}\)
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Find the solution set of the inequality \(x - \frac{4}{5} \leq \frac{1}{5}\), if the domain is the set \(\{-2, -1, 0, 1, 2\}\)
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A rectangular sheet of metal has length 44 cm and breadth 10 cm. It is folded to form a cylinder with the breadth becoming the height. Calculate
\((i)\) the radius of the cylinder formed;
\((ii)\) the volume of the cylinder.
[Take \(\pi = \frac{22}{7}\)]
Solution
Solution
Solution
Question 5
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Using a pair of compasses and a ruler only,
\(\hspace{0.5cm} i)\) Construct the triangle \(ABC\) with \(|AB| = 8\) cm, \(|BC| = 8\) cm and \(|AC| = 7\) cm.
\(\hspace{0.5cm} ii)\) Bisect \(ABC\) and let the bisector meet \(AC\) at \(D\). Produce \(|BD|\) to \(P\) such that \(|BD| = |DP|\). Join \(AP\) and \(CP\).
Solution
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