Definition and Types

Lesson Video

Watch this comprehensive explanation on definition and types of polynomial functions.

A polynomial function is an algebraic expression consisting of variables and coefficients, involving only addition, subtraction, multiplication, and non-negative integer exponents.

General form of a polynomial:

\[ P(x) = a_nx^n + a_{n-1}x^{n-1} + \cdots + a_1x + a_0 \]

Where \( a_n \neq 0 \) and \( n \) is a non-negative integer.

Degree of Polynomial:

The highest power of the variable (n) determines the degree:

  • Constant: Degree 0 (e.g., \( P(x) = 5 \))
  • Linear: Degree 1 (e.g., \( P(x) = 2x + 3 \))
  • Quadratic: Degree 2 (e.g., \( P(x) = x^2 - 5x + 6 \))
  • Cubic: Degree 3 (e.g., \( P(x) = x^3 + 2x^2 - x + 5 \))

Leading Coefficient:

  • The leading coefficient of a polynomial is the term with the highest degree (\( a_n \)).
  • The leading coefficient cannot be zero (\( a_n \ne 0 \))

Linear Polynomials

Linear Polynomials are first-degree polynomials of the form below:

\[ f(x) = ax + b \quad (a \neq 0) \]

Characteristics of linear Polynomials:

  • Straight line graphs
  • One real root (x-intercept)
  • Constant slope (gradient)

Graph of \( f(x) = 2x - 1 \) with the root at \( x = 0.5 \)


Quadratic Polynomials

Second-degree polynomials are of the form:

\[ f(x) = ax^2 + bx + c \quad (a \neq 0) \]

Graph Characteristics:

  • Parabolic shape
  • Vertex (turning point)
  • Axis of symmetry
  • 0, 1, or 2 real roots

Graph of \( f(x) = x^2 -5x + 6 \) with the root at \( x = 2 \) and \( x = 3 \)


Cubic Functions

Third-degree polynomials of the form:

\[ f(x) = ax^3 + bx^2 + cx + d \quad (a \neq 0) \]

Example cubic function:

\[ f(x) = x^3 - 3x^2 - x + 3 \]

Graph Characteristics:

  • "S"-shaped curve
  • 1 to 3 real roots
  • Possible 1 or 2 turning points

Graph of \( f(x) = x^3 - 3x^2 - x + 3 \) with the roots at \( x = -1 \), \( x = 1 \) and \( x = 3 \)


Practice Exercise

Question 1

Which of the following is a polynomial function?

  1. \( f(x) = 3x^2 - 5x + 7 \)
  2. \( f(x) = \frac{2}{x} + 1 \)
  3. \( f(x) = \sqrt{x} + 4 \)
  4. \( f(x) = x^{-2} + 3x \)

Answer: A

\( f(x) = 3x^2 - 5x + 7 \) is a polynomial because its variable has only non-negative integer exponents.

The other expressions contain a negative exponent, a variable in the denominator, or a fractional exponent.

Question 2

Consider the polynomial \[ P(x) = 4x^5 - 3x^3 + 7x^2 - 2x + 9. \] State:

  1. the degree of the polynomial;
  2. the leading coefficient;
  3. the constant term.

The polynomial is \[ P(x) = 4x^5 - 3x^3 + 7x^2 - 2x + 9. \]

(a) Degree: \(5\), because the highest power of \(x\) is \(5\).

(b) Leading coefficient: \(4\), because \(4x^5\) is the term with the highest degree.

(c) Constant term: \(9\).

Question 3

Classify each of the following polynomial functions as constant, linear, quadratic, or cubic.

  1. \( f(x) = 8 \)
  2. \( g(x) = 5x - 2 \)
  3. \( h(x) = 2x^2 + 3x - 1 \)
  4. \( p(x) = x^3 - 4x + 6 \)

(a) \( f(x) = 8 \) — Constant polynomial (degree \(0\)).

(b) \( g(x) = 5x - 2 \) — Linear polynomial (degree \(1\)).

(c) \( h(x) = 2x^2 + 3x - 1 \) — Quadratic polynomial (degree \(2\)).

(d) \( p(x) = x^3 - 4x + 6 \) — Cubic polynomial (degree \(3\)).

Question 4

Consider the polynomial \[ f(x) = -2x^3 + 5x^2 - 7x + 4. \] Which statement about the polynomial is correct?

  1. It is a quadratic polynomial with leading coefficient \(5\).
  2. It is a cubic polynomial with leading coefficient \(-2\).
  3. It is a cubic polynomial with leading coefficient \(4\).
  4. It is a linear polynomial with leading coefficient \(-2\).

Answer: B

The highest power of \(x\) is \(3\), so the polynomial is cubic.

The term containing the highest power is \(-2x^3\), so the leading coefficient is \(-2\).

Question 5

Match each polynomial type with its correct graph characteristic.

  1. Linear polynomial
  2. Quadratic polynomial
  3. Cubic polynomial

Characteristics:

  1. Parabolic shape with a possible turning point
  2. S-shaped curve with up to two turning points
  3. Straight-line graph with constant gradient

Answers:

(a) Linear polynomial → (iii)
A linear polynomial has a straight-line graph with constant gradient.

(b) Quadratic polynomial → (i)
A quadratic polynomial has a parabolic graph and may have a turning point.

(c) Cubic polynomial → (ii)
A cubic polynomial generally has an S-shaped graph and may have one or two turning points.

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Roots and Zeros

Lesson Video

Watch this comprehensive explanation on roots and zeros of polynomial functions.

Roots and Zeros

A root (or zero) of a polynomial, $p(x)$, is a solution to \( p(x) = 0 \).

For \( p(x) = x^2 - 4 \):

\( \begin{aligned} & \Rightarrow p(x) &= 0 \\ & \Rightarrow x^2 - 4 &= 0 \\ & \Rightarrow (x - 2)(x + 2) &= 0 \end{aligned} \)

if $ x - 2 = 0$
$\Rightarrow x = 2$

if $ x + 2 = 0$
$\Rightarrow x = -2$

Thus, \( x = -2 \) and \( x = 2 \) are roots or zeros of the polynomial.

Roots of the polynomial

Fundamental Theorem of Algebra:

A polynomial of degree \( n \) has exactly \( n \) roots (real or complex, counting multiplicities).

Practice Exercise

Question 1

Find the zeros of the polynomial $f(x) = 2x^2 + 3x - 2$.

Question 2

Find the roots of the polynomial $g(x) = x^2 - 5x + 6$.

Question 3

Solve for the zeros of $h(x) = x^2 - 9$.

Question 4

Determine the x-intercepts of the polynomial $p(x) = x^2 + 2x - 8$.

Question 5

Find all roots of $q(x) = x^2 - 7x + 12$.

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Addition & Subtraction

Lesson Video

Watch this comprehensive explanation on addtion and subtraction of polynomial functions.

Addition and Subtraction

Combine like terms (terms with the same degree):

Example:

\[ (3x^2 + 2x - 5) + (2x^2 - 4x + 1) = 5x^2 - 2x - 4 \]

Practice Exercise

Question 1

Given $h(x) = x^4 + 2x^3 - x^2 + 4x - 7$ and $g(x) = 2x^3 + 3x^2 - 5x - 5$, find $h(x) + 2g(x)$.

Question 2

Given $h(x) = x^4 + 2x^3 - x^2 + 4x - 7$ and $g(x) = 2x^3 + 3x^2 - 5x - 5$, find $h(x) - 2g(x)$.

Question 3

Given $h(x) = x^4 + 2x^3 - x^2 + 4x - 7$ and $g(x) = 2x^3 + 3x^2 - 5x - 5$, find $3h(x) - 2g(x)$.

Question 4

Given $h(x) = x^4 + 2x^3 - x^2 + 4x - 7$ and $g(x) = 2x^3 + 3x^2 - 5x - 5$, find $g(x) - h(x)$.

Question 5

Given $h(x) = x^4 + 2x^3 - x^2 + 4x - 7$ and $g(x) = 2x^3 + 3x^2 - 5x - 5$, find $2h(x) - 2g(x)$.

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Multiplication

Lesson Video

Watch this comprehensive explanation on multiplication of polynomial functions.

Multiplication

Use the distributive property (FOIL method for binomials):

Example:

\[ (x + 2)(x - 3) = x^2 - 3x + 2x - 6 = x^2 - x - 6 \]

Practice Exercise

Question 1

Multiply and simplify: \( (x + 2)(x^2 - 3x + 4) \).

Question 2

Multiply and simplify: \( (x - 3)(x^2 + 2x + 5) \).

Expand:

\( x(x^2 + 2x + 5) - 3(x^2 + 2x + 5) = x^3 + 2x^2 + 5x - 3x^2 - 6x - 15 \)

Simplify:

\( x^3 - x^2 - x - 15 \)

Question 3

Multiply and simplify: \( (2x + 1)(x^2 - x + 4) \).

Expand:

\( 2x(x^2 - x + 4) + 1(x^2 - x + 4) = 2x^3 - 2x^2 + 8x + x^2 - x + 4 \)

Simplify:

\( 2x^3 - x^2 + 7x + 4 \)

Question 4

Multiply and simplify: \( (x^2 + 3x - 2)(x + 4) \).

Expand:

\( x^2(x + 4) + 3x(x + 4) - 2(x + 4) = x^3 + 4x^2 + 3x^2 + 12x - 2x - 8 \)

Simplify:

\( x^3 + 7x^2 + 10x - 8 \)

Question 5

Multiply and simplify: \( (3x - 2)(2x^2 + x - 5) \).

Expand:

\( 3x(2x^2 + x - 5) - 2(2x^2 + x - 5) = 6x^3 + 3x^2 - 15x - 4x^2 - 2x + 10 \)

Simplify:

\( 6x^3 - x^2 - 17x + 10 \)

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Division of Polynomials

Lesson Video

Watch this comprehensive explanation on division of polynomial functions.

Division of Polynomials

Polynomial long division follows similar steps to numerical division:

Divide \( x^3 - 2x^2 - 4x + 8 \) by \( x - 2 \):

1. Divide leading terms: \( x^3 ÷ x = x^2 \)

2. Multiply divisor by \( x^2 \): \( x^3 - 2x^2 \)

3. Subtract and bring down next term

4. Repeat process until remainder is of lower degree than divisor

Result: \( x^2 - 4 \) with remainder 0

Practice Exercise

Question 1

Divide \( 2x^3 + 3x^2 - 5x + 6 \) by \( x + 2 \).

Watch the video below for a clearer understanding of the question.

Question 2

Divide \( x^3 - 6x^2 + 11x - 6 \) by \( x - 1 \).

Watch the video below for a clearer understanding of the question.

Question 3

Divide \( x^3 + 2x^2 - x - 2 \) by \( x + 1 \).

Watch the video below for a clearer understanding of the question.

Question 4

$\dfrac{x^4 - 3x^3 - 3}{x^3 - x^2}$

Watch the video below for a clearer understanding of the question.

Question 5

Divide \( 2x^4 + 3x^3 - x^2 + 5x - 6 \) by \( x^2 + x - 2 \).

Watch the video below for a clearer understanding of the question.

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Remainder Theorem

Lesson Video

Watch this comprehensive explanation on remainder theorem.

If a polynomial \( P(x) \) is divided by \( (x - a) \), the remainder is \( P(a) \).

Given \( P(x) = x^3 - 2x^2 + 3x - 5 \), find remainder when divided by \( x - 1 \):

\[ P(1) = (1)^3 - 2(1)^2 + 3(1) - 5 = -3 \]

Thus, remainder is -3.

Application:

Quickly evaluate remainders without performing full division.

Proof of Remainder Theorem

From polynomial division:

\[ P(x) = (x - a)Q(x) + R \]

Where \( Q(x) \) is the quotient and \( R \) is the remainder (constant).

Substitute \( x = a \):

\[ P(a) = (a - a)Q(a) + R = R \]

Practice Problem

Find the remainder when \( P(x) = 2x^3 - 5x^2 + 4x - 1 \) is divided by \( x + 2 \).

Using Remainder Theorem with \( x = -2 \):

\[ P(-2) = 2(-2)^3 - 5(-2)^2 + 4(-2) - 1 \] \[ = -16 - 20 - 8 - 1 = -45 \]

Practice Exercise

Question 1

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Factor Theorem

Lesson Video

Watch this comprehensive explanation on factor theorem.

For a polynomial \( P(x) \), \( (x - a) \) is a factor if and only if \( P(a) = 0 \).

Show \( x - 2 \) is a factor of \( P(x) = x^3 - 3x^2 + 4 \):

\[ P(2) = 8 - 12 + 4 = 0 \]

Thus, \( x - 2 \) is a factor.

Application:

Factorizing polynomials and finding roots.

Using Factor Theorem

Steps to factorize a polynomial:

  1. Find possible roots using Rational Root Theorem (factors of constant term ÷ factors of leading coefficient)
  2. Test possible roots using Factor Theorem
  3. Once a root \( a \) is found, factor out \( (x - a) \) using synthetic division
  4. Repeat with the resulting polynomial until fully factorized

Factorize \( P(x) = x^3 - 3x^2 - x + 3 \):

Possible roots: ±1, ±3

Test \( x = 1 \): \( P(1) = 1 - 3 - 1 + 3 = 0 \) → \( (x - 1) \) is a factor

Using synthetic division:

Quotient: \( x^2 - 2x - 3 \)

Final factorization: \( (x - 1)(x + 1)(x - 3) \)

Relationship Between Theorems

The Factor Theorem is a special case of the Remainder Theorem where the remainder is zero.

\[ P(a) = 0 \iff (x - a) \text{ is a factor of } P(x) \]

Practice Problem

Show that \( x + 1 \) is a factor of \( P(x) = 2x^3 + x^2 - 5x + 2 \) and hence factorize completely.

1. Test \( P(-1) = 2(-1)^3 + (-1)^2 - 5(-1) + 2 = -2 + 1 + 5 + 2 = 6 \neq 0 \)

Wait, this suggests \( x + 1 \) is NOT a factor. Let's try another approach.

Testing \( x = 1 \): \( P(1) = 2 + 1 - 5 + 2 = 0 \) → \( x - 1 \) is a factor

Using synthetic division:

Quotient: \( 2x^2 + 3x - 2 \)

Further factorized: \( (x - 1)(2x - 1)(x + 2) \)

Practice Exercise

Question 1

Find the remainder when \( P(x) = x^4 - 2x^3 + 3x - 5 \) is divided by \( x - 2 \).

\[ P(2) = 16 - 16 + 6 - 5 = 1 \]

Question 2

Show that \( x - 3 \) is a factor of \( P(x) = x^3 - 6x^2 + 11x - 6 \) and factorize completely.

\( P(3) = 27 - 54 + 33 - 6 = 0 \)

Synthetic division gives \( x^2 - 3x + 2 \)

Complete factorization: \( (x - 1)(x - 2)(x - 3) \)

Question 3

Given that \( x - 2 \) and \( x + 1 \) are factors of \( P(x) = x^4 + ax^3 + bx^2 - 4x - 4 \), find the values of \( a \) and \( b \).

Using \( P(2) = 0 \): \( 16 + 8a + 4b - 8 - 4 = 0 \) → \( 8a + 4b = -4 \)

Using \( P(-1) = 0 \): \( 1 - a + b + 4 - 4 = 0 \) → \( -a + b = -1 \)

Solving simultaneously: \( a = 0 \), \( b = -1 \)

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Quick Test

This section contains 100 multiple choice questions. You have 60 minutes to complete it.

Each question has four options labeled A to D. Select the correct answer for each question.

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